6 HCl (aq) + 2 KMnO4 (aq) + 5 NaNO2 (aq) → 2 MnCl2 (aq) + 2 KCl (aq) + 5 NaNO3 (aq) + 4 H2O (ℓ)

Back to reactions list

 

Stoichiometry

Enter a mass or volume in one of the boxes below. Upon hitting submit, the stoichiometric equivalents will be calculated for the remaining reactants and products. All gases are assumed to be at STP.

HCl            Mass: g  or Solution Volume: mL of Concentration: mol/L
KMnO4          Mass: g  or Solution Volume: mL of Concentration: mol/L
NaNO2          Mass: g  or Solution Volume: mL of Concentration: mol/L
MnCl2          Mass: g  or Solution Volume: mL of Concentration: mol/L
KCl            Mass: g  or Solution Volume: mL of Concentration: mol/L
NaNO3          Mass: g  or Solution Volume: mL of Concentration: mol/L
H2O            Mass: g

Enthalpy of Reaction

[2ΔHf(MnCl2 (aq)) + 2ΔHf(KCl (aq)) + 5ΔHf(NaNO3 (aq)) + 4ΔHf(H2O (ℓ))] - [6ΔHf(HCl (aq)) + 2ΔHf(KMnO4 (aq)) + 5ΔHf(NaNO2 (aq))]
[2(-555.13) + 2(-419.55) + 5(-447.46) + 4(-285.83)] - [6(-167.15) + 2(-793.81) + 5(-344.7)] = -1015.96 kJ
-1,015.96 kJ     (exothermic)

Entropy Change

[2ΔSf(MnCl2 (aq)) + 2ΔSf(KCl (aq)) + 5ΔSf(NaNO3 (aq)) + 4ΔSf(H2O (ℓ))] - [6ΔSf(HCl (aq)) + 2ΔSf(KMnO4 (aq)) + 5ΔSf(NaNO2 (aq))]
[2(39.32) + 2(158.98) + 5(205.44) + 4(69.91)] - [6(56.48) + 2(293.71) + 5(199.16)] = -218.66 J/K
-218.66 J/K     (decrease in entropy)

Free Energy of Reaction (at 298.15 K)

From ΔGf° values:
[2ΔGf(MnCl2 (aq)) + 2ΔGf(KCl (aq)) + 5ΔGf(NaNO3 (aq)) + 4ΔGf(H2O (ℓ))] - [6ΔGf(HCl (aq)) + 2ΔGf(KMnO4 (aq)) + 5ΔGf(NaNO2 (aq))]
[2(-490.53) + 2(-414.55) + 5(-373.24) + 4(-237.18)] - [6(-131.25) + 2(-730.57) + 5(-299.14)] = -880.74 kJ
-880.74 kJ     (spontaneous)

From ΔG = ΔH - TΔS:
-950.77 kJ     (spontaneous)

Equilibrium Constant, K (at 298.15 K)

2.03028954630832E+154
This process is favorable at 25°C.