2 KOH (aq) + 1 (NH4)2SO4 (s) → K2SO4 (aq) + 2 H2O (ℓ) + 2 NH3 (g)

Back to reactions list

 

Reaction Type:

Double Displacement/Decomposition of Ammonium Hydroxide

Stoichiometry

Enter a mass or volume in one of the boxes below. Upon hitting submit, the stoichiometric equivalents will be calculated for the remaining reactants and products. All gases are assumed to be at STP.

KOH            Mass: g  or Solution Volume: mL of Concentration: mol/L
(NH4)2SO4      Mass: g
K2SO4          Mass: g  or Solution Volume: mL of Concentration: mol/L
H2O            Mass: g
NH3            Mass: g  or Gas Volume: L

Enthalpy of Reaction

[1ΔHf(K2SO4 (aq)) + 2ΔHf(H2O (ℓ)) + 2ΔHf(NH3 (g))] - [2ΔHf(KOH (aq)) + 1ΔHf((NH4)2SO4 (s))]
[1(-1414.07) + 2(-285.83) + 2(-46.11)] - [2(-482.39) + 1(-1180.85)] = 67.6800000000003 kJ
67.68 kJ     (endothermic)

Free Energy of Reaction (at 298.15 K)

From ΔGf° values:
[1ΔGf(K2SO4 (aq)) + 2ΔGf(H2O (ℓ)) + 2ΔGf(NH3 (g))] - [2ΔGf(KOH (aq)) + 1ΔGf((NH4)2SO4 (s))]
[1(-1311.23) + 2(-237.18) + 2(-16.48)] - [2(-440.58) + 1(-901.9)] = -35.4900000000002 kJ
-35.49 kJ     (spontaneous)

From ΔG = ΔH - TΔS:
-35.48 kJ     (spontaneous)

Equilibrium Constant, K (at 298.15 K)

1651676.40166425
This process is favorable at 25°C.