## CaMoO4 (s) → Ca+2 (aq) + MoO4-2 (aq)

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## Reaction Type:

Dissociation of an ionic compound in water

## Enthalpy of Reaction

[1ΔHf(Ca+2 (aq)) + 1ΔHf(MoO4-2 (aq))] - [1ΔHf(CaMoO4 (s))]
[1(-542.83) + 1(-997.88)] - [1(-1541.39)] = 0.680000000000064 kJ
0.68 kJ     (endothermic)

## Entropy Change

[1ΔSf(Ca+2 (aq)) + 1ΔSf(MoO4-2 (aq))] - [1ΔSf(CaMoO4 (s))]
[1(-53.14) + 1(27.2)] - [1(122.59)] = -148.53 J/K
-148.53 J/K     (decrease in entropy)

## Free Energy of Reaction (at 298.15 K)

From ΔGf° values:
[1ΔGf(Ca+2 (aq)) + 1ΔGf(MoO4-2 (aq))] - [1ΔGf(CaMoO4 (s))]
[1(-553.54) + 1(-836.38)] - [1(-1434.69)] = 44.77 kJ
44.77 kJ     (nonspontaneous)

From ΔG = ΔH - TΔS:
44.96 kJ     (nonspontaneous)

## Equilibrium Constant, K (at 298.15 K)

1.4328440068e-008
This process is not favorable at 25°C.

Enter an initial concentration for the ionic compound. Upon hitting submit, Ksp (1.4328440068e-008) will be used to calculate the equilibrium concentration for all species.

 CaMoO4 Ca+2 MoO4-2 Initial M 0 0 Change -x +x +x Equilibrium