CaBr2 (s) → Ca+2 (aq) + 2 Br-1 (aq)

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Reaction Type:

Dissociation of an ionic compound in water

Enthalpy of Reaction

[1ΔHf(Ca+2 (aq)) + 2ΔHf(Br-1 (aq))] - [1ΔHf(CaBr2 (s))]
[1(-542.83) + 2(-121.55)] - [1(-683.25)] = -102.68 kJ
-102.68 kJ     (exothermic)

Free Energy of Reaction (at 298.15 K)

From ΔGf° values:
[1ΔGf(Ca+2 (aq)) + 2ΔGf(Br-1 (aq))] - [1ΔGf(CaBr2 (s))]
[1(-553.54) + 2(-103.97)] - [1(-664.13)] = -97.35 kJ
-97.35 kJ     (spontaneous)

From ΔG = ΔH - TΔS:
-97.31 kJ     (spontaneous)

Equilibrium Constant, K (at 298.15 K)

1.137446854e+017
This process is favorable at 25°C.

Enter an initial concentration for the ionic compound. Upon hitting submit, Ksp (1.137446854e+017) will be used to calculate the equilibrium concentration for all species.

CaBr2 Ca+2 Br-1
Initial M   0 0
Change -x +x +2x
Equilibrium